So the equation of the perpendicular line is of the form y = 3x /2 + b. The equation of a line is such that its highest exponent on its.
Find The Equation Of A Line Perpendicular To 2X 3Y12. ⇒ y = 2 3 x − 4 ← in standard form. Divide all terms by −3.
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Y = m x + b y = m x + b. You can put this solution on your website! Add 2 to both sides.
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By using this website, you agree to our cookie policy. Add 2 to both sides. Y = m x + b y = m x + b. Equation of diameter given are 2x−3y=−12and x+4y=5.
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The given line is 2x + 3y = 12, which can be written as (\frac{x}{6}+\frac{y}{4}=1).…(1) so, the coordinates of the points a and b are (6, 0) and (0, 4), respectively. One such line would be y=3x/2+4 (green line). Subtract from both sides of. Find any equation parallel to the line 2x+3y=12. Y = m x + b y =.
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You can put this solution on your website! (2) subtracting (1) from (2), we get. Add 2 to both sides. Subtract from both sides of. Equation of diameter given are 2x−3y=−12and x+4y=5.
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Add 2 to both sides. Subtract 3y from both sides. ∙ xy = mx + b. Add 2 to both sides. Subtract 2x from both sides.
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Now, y intercept is b (put x=0). Plugging in the point given into the equation y = 1/2 x + b and solving for b, we get b = 6. ∙ xy = mx + b. Subtract 3y from both sides. Divide all terms by −3.
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If o is the origin ,. So the slope of the line perpendicular to this line will be 3/2. You can put this solution on your website! Subtract 3y from both sides. The form y = mx + b gives the equation of a straight line where m is the slope of the line (the gradient) and b is the.
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Now, y intercept is b (put x=0). The given line is 2x + 3y = 12, which can be written as (\frac{x}{6}+\frac{y}{4}=1).…(1) so, the coordinates of the points a and b are (6, 0) and (0, 4), respectively. Subtract 3y from both sides. One such line would be y=3x/2+4 (green line). Which equation represents a line perpendicular to the line.
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So the slope of the line perpendicular to this line will be 3/2. You can put this solution on your website! The form y = mx + b gives the equation of a straight line where m is the slope of the line (the gradient) and b is the intercept of the line and the y axis. ∙ xy =.
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A line that is perpendicular must have a negative reciprocal slope: Asked jul 11, 2018 in straight lines by chaya ( 68.5k points) The form y = mx + b gives the equation of a straight line where m is the slope of the line (the gradient) and b is the intercept of the line and the y axis. So.
